Mot so bai tham khao!!

Co mot so de thi tham khao,minh lay tu trang www.diendantinhoc.com
(da chinh sua de chay duoc rui), moi nguoi tham khao nhe!!



1. Xây dựng câu trúc Sinhvien
o Hoten – có 30 ký tự
o Tuoi - kiểu int
2. Định nghĩa kiểu dữ liệu mới Svien dựa trên cấu trúc sinh viên (sử dụng từ khoá typedef)
3. Xây dựng chương trình
o Tạo menu gồm:
 1. Nhập dữ liệu
 2. In thông tin
 3. Sắp xếp theo tên
 4. Đảo vị trí
 5. Kết thúc
4. Khi chọn vào mục 1 -> Nhập dữ liệu cho 5 sinh viên, viết hàm nhập riêng và sử dụng con trỏ làm tham số cho việc truyền cấu trúc.
5. Chọn mục 2 -> in danh sách sinh viên đã nhập: viết hàm riêng, dùng tham số là con trỏ
6. Chọn mục 3: Sắp xếp theo tên: sắp xếp các sinh viên theo thứ tự tăng dần A-> Z
o Viết hàm riêng, dùng con trỏ
o Có thể viết thêm 1 hàm để đảo vị trí 2 sinh viên
7. Chọn mục 4: Đảo vị trí các sinh viên từ sau ra trước
o 1-> n
o 2-> n-1
o …
8. Chọn mục 5: Kết thúc chương trình

Con day code chay:

#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<stdlib.h>

typedef struct sinhvien
{
char hoten[30];
int tuoi;
float diem;
}sv;


//==============================

int menu()
{
int phim;

printf("\nTAO MENU:");
printf("\n\t 1.Nhap du lieu.");
printf("\n\t 2.In thong tin.");
printf("\n\t 3.Sap xep theo ten.");
printf("\n\t 4.Dao vi tri.");
printf("\n\t 5.In ra file.");
printf("\n\t 6.Thoat.");
printf("\nCHON 1 CHUC NANG TREN:--->>");
scanf("%d",&phim);
printf("\n--------------------------");
return phim;
}



//=================================


//NHAP THONG TIN VE SINH VIEN
void nhap(sv *sv1,int n)
{
int i=0;
float tam;
for(i=0;i<n;i++)
{
printf("\nNhap thong tin sinh vien:");
printf("\n\tHo ten:");
fflush(stdin);
gets(sv1[i].hoten);

printf("\n\tTuoi:");
scanf("%d",&(sv1+i)->tuoi);

printf("\n\tDiem:");
scanf("%f",&tam);
sv1[i].diem= tam;
}
}



//=================================

//IN THONG TIN SV RA MAN` HINH`
void in(sv *sv1,int n)
{
int i=0;
for (i=0;i<n;i++)
{
printf("\nIn ra thong tin ve sinh vien:");
printf("\n\t Ho ten :%s",(sv1 +i)->hoten);
printf("\n\t Tuoi :%d",(sv1 +i)->tuoi);
printf("\n\t Diem :%.2f",(sv1 +i)->diem);
}
}




//=================================

void sapxep(sv *sv1,int n)
{
int i,j,c;
sv tg;
for(i=0;i<n;i++)
for(j=i+1;j<n;j++)
{
c=strcmp((sv1+i)->hoten,(sv1+j)->hoten); //DUng` con tro

// Co the dung` mang? nhu sau : c=strcmp(nv1[i].hoten,nv1[j].hoten);
if(c>0)
{
tg=sv1[i];
sv1[i]=sv1[j];
sv1[j]=tg;
}
}
}

//=================================
void daovitri(sv *sv1,int n)
{
int i,j;
sv tam;
for(i=0,j=n-1;i<=n/2;i++,j--)
{
tam=sv1[i];
sv1[i]=sv1[j];
sv1[j]=tam;
}
}

//=================================
//LUU THONG TIN VE SV RA FILE
void savefile(char *tenfile,sv *sv1,int n)
{
FILE *fp;
int i;
fp = fopen(tenfile , "w");
if (fp==NULL)
{
printf("\nKhong mo duoc Flie");
}
else
{
for(i=0;i<n;i++)
{
fprintf(fp, "\n Sinh vien thu' %d:", i+1);
fprintf(fp, "\n\tHo ten: %s \n\tTuoi: %d \n\tDiem: %.2f", (sv1+i)->hoten, (sv1+i)->tuoi,
(sv1+i)->diem);
}

fclose(fp);
}

}

//==========================================================================



//HAM` CHINH' CUA CHUONG TRINH`
void main()
{
sv sv1[3];

do
{

int phim;
phim= menu();

switch(phim)
{
case 1:
nhap(sv1,3);
break;
case 2:
in(sv1,3);
break;
case 3:
sapxep(sv1,3);
printf("\nBan da sap xep ten theo thu tu bang chu cai.");
break;

case 4:
daovitri(sv1,3);
printf("\nMang da dao");
break;

case 5:
savefile("DATA.TXT", sv1, 3);
printf("\nBan da in ra file thanh cong:");
break;



case 6:exit(1);
break;

default:
printf("\nChon sai-Chon lai.");
break;
}
getch();
}
while(1);
}

Con day la mot so de thi ly thuyet(chay tho):


45. main()
{ int x=5;
for(;x!=0;x--)
{ printf("x=%d\n", x--); }
}

A. 5, 3, 1

B. 4, 3, 2, 1, 0

C. 5, 4, 3, 2,1

D. none of the above<Vong` lap se chay vo han>
________________________________________

46. main()
{ int x=5;
clrscr();
for(;x<= 0;x--)
{ printf("x=%d ", x--); }
}

A. 5, 3, 1, -1, 3

B. 5, 2, 1

C. 5, 3, 1

D. None of the above.
________________________________________

47. main()
{
{ unsigned int bit=256;
printf("%d", bit);
}
{ unsigned int bit=512;
printf("%d", bit); }
}

A. 256, 512

B. 512, 512

C. 256, 256


________________________________________

48.main()
{ int i;
clrscr();
for(i=0;i<5;i++)
{ printf("%d\n", 1L << i); } }

A. 1, 2, 4, 8, 16

B. 0, 1, 2, 4, 8

C. 0, 1, 2, 3, 4

D. 5, 4, 3, 2, 1
________________________________________

49. main()
{ signed int bit=512, i=5;
for(;i;i--)
{ printf("%d\n", bit = (bit >> (i - (i -1)))); } }

A. 128, 64, 32, 16, 8

B. 256, 128, 64, 32, 16

C. 512, 256, 128, 64, 32

D. 64, 32, 16, 8, 4
________________________________________
50. main()
{ signed int bit=512, i=5; for(;i;i--)
{ printf("%d\n", bit >> (i - (i -1))); } }

A. 512, 512, 512, 512, 512

B. 256, 256, 0, 0, 0

C. 512, 256, 0, 0, 0

D. 256, 256, 256, 256, 256
________________________________________
51 . main()
{ if (!(1&&0))
{ printf("OK I am done.");
}
else { printf("OK I am gone."); } }

A. none of the above

B. compile error

C. OK I am gone

D. OK I am done
________________________________________

52 . main()
{ if ((1||0) && (0||1))
{ printf("OK I am done."); }
else { printf("OK I am gone."); } }

A. none of the above

B. compile error

C. OK I am gone

D. OK I am done
________________________________________

53. main() { signed int bit=512, mBit; { mBit = ~bit; bit = bit & ~bit ; printf("%d %d", bit, mBit); } }

A. 0, -513
B. 512, 0

C. 0, 513

D. 0, 0
________________________________________

54 . What would be the output of the following program?
main()
{ int i=4;
switch(i)
{
default: printf("\n A mouse is an elephant built by the Japanese"); case 1: printf(" Breeding rabbits is a hair raising experience"); break; case 2: printf("\n Friction is a drag"); break; case 3: printf("\n If practice make perfect, then nobody's perfect"); } }

A. A mouse is an elephant built by the Japanese

B. Breeding rabbits is a hare raising experience

C. A mouse is an elephant built by the Japanese Breeding rabbits is a hare raising experience

D. None of the above
________________________________________

55 . What is the output of the following program?
#define SQR(x) (x*x)
main() { int a,b=3; a= SQR(b+2);
printf("%d",a); }

A. 25

B. 11

C. Error

D. Garbage Value
________________________________________

56 . In which line of the following, an error would be reported? 1. #define CIRCUM® (3.14*R*R); 2. main() 3. { 4. float r=1.0,c; 5. c= CIRCUM®; 6. printf("\n%f",c); 7. if(CIRCUM®)==6.28) 8. printf("\nGobbledygook"); 9. }

A. Line 1

B. Line 5

C. Line 6

D. Line 7
________________________________________

57 . We should not read after a write to a file without an intervening call to fflush(), fseek() or rewind()

A. True

B. False
________________________________________

14 . If the program (myprog) is run from the command line as myprog 1 2 3 , What would be the output?
main(int argc, char *argv[]) { int i; for(i=0;i<argc;i++) printf("%s",argv[i]); }

A. 1 2 3

B. C:\MYPROG.EXE123//Moi may’ cho mot ket qua khac nhau.

C. MYP

D. None of the above
________________________________________

58 . If the following program (myprog) is run from the command line as myprog 1 2 3, What would be the output?
main(int argc, char *argv[]) { int i,j=0; for(i=0;i<argc;i++) j=j+ atoi(argv[i]); printf("%d",j); }

A. 1 2 3

B. 6

C. error

D. "123"
________________________________________

59 . If the following program (myprog) is run from the command line as myprog monday tuesday wednesday thursday What would be the output?
main(int argc, char *argv[]) { while(--argc >0) printf("%s",*++argv); }

A. myprog monday tuesday wednesday thursday

B. monday tuesday wednesday thursday

C. mondaytuesdaywednesdaythursday

D. myprog tuesday thursday
________________________________________

60 . What would be the output of the following program?
main() {
int y=128;
const int x=y;
printf("%d",x);
}

A. 128

B. Garbage value

C. Error

D. 0
________________________________________

61 . Following declarations are same:
const char *s; char const *s;

A. True

B. False
________________________________________

62 . What would be the output of the following program?
main()
{ char near * near *ptr1;
char near * far *ptr2;
char near * huge *ptr3;
printf("%d %d %d",sizeof(ptr1),sizeof(ptr2),sizeof(ptr3));
}

A. 1 1 1

B. 1 2 4

C. 2 4 4

D. 4 4 4

E. Error
________________________________________

63 . Following declarations are different from one another const char *const s; char const *const s;

A. True

B. False
________________________________________

64 . If the following program (myprog) is run from the command line as myprog friday tuesday sunday, What would be the output?
main(int argc, char*argv[])
{ printf("%c",**++argv); }

A. m

B. f

C. myprog

D. Friday
E.Runtime error
________________________________________

65 . If the following program (myprog) is run from the command line as myprog friday tuesday sunday, What would be the output?

main(int argc, char *argv[])
{ printf("%c",*++argv[1]); }

A. r

B. f

C. m

D. y
E.< Runtime error>
________________________________________
66 . Would the following program compile? main() { int a=10,*j; void *k; j=k=&a; j++; k++; printf("\n%u%u",j,k); }

A. True

B. False
________________________________________

67 . According to ANSI specifications which is the correct way of declaring main() when it receives command line arguments?

A. main(int argc, char *argv[])

B. main(argc,argv) int argc; char *argv[];

C. main() {int argc; char *argv[]; }

D. None of the above
________________________________________

68 . What would be the output of the following program?
main()
{ const int x=5; int *ptrx; ptrx=&x; *ptrx=10; printf("%d",x); }

A. 5

B. 10
C. Error

D. Garbage Value <Gia’ tri vo nghia~>








69. main()
{ int i; clrscr(); printf("%d", &i)+1; scanf("%d", i)-1; }

A. Runtime error. Access violation

B. Compile error. Illegal syntax

C. None of the above

D. Runtime error
________________________________________

70 . main(int argc, char *argv[]) { (main && argc) ? main(argc-1, NULL) : return 0; }

A. Gets into Infinite loop

B. Compile error. Illegal syntax
C. None of the above

D. Runtime error.
________________________________________

71. main() { int i; float *pf; pf = (float *)&i; *pf = 100.00; printf("\n %d", i); }

A. Some Integer not 100

B. 100

C. Runtime error.

D. None of the above
________________________________________
72. main() { int i = 0xff ; printf("\n%d", i<<2); }

A. 1020

B. 512

C. 4

D. 1024
________________________________________

73. #define SQR(x) x * x
main()
{ printf("%d", 225/SQR(15)); }

A. 15

B. 225

C. 1

D. none of the above
________________________________________

74. union u { struct st { int i : 4; int j : 4; int k : 4; int l; }st; int i; }u; main() { u.i = 100; printf("%d, %d, %d",u.i, u.st.i, u.st.l); }

A. 40, 4, 0

B. 100, 4, 0

C. 0, 0, 0

D. 4, 4, 0
________________________________________

75 . union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); }

A. 1, 100, 1

B. 40, 4, 4

C. 4, 4, 4

D. None of the Above
________________________________________

76 . main() { int i, j, *p; i = 25; j = 100; p = &i; // Address of i is assigned to pointer p printf("%f", i/(*p) ); // i is divided by pointer p }

A. Compile error

B. 1.00000

C. Runtime error.

D. Runtime error.
________________________________________

77 . main() { int i, j; scanf("%d %d"+scanf("%d %d", &i, &j)); printf("%d %d", i, j); }

A. Compile error

B. 0, 0

C. Runtime error.

D. the first two values entered by the user<nhap vao 2 gia tri>
________________________________________

78 . main() { char *p = "hello world"; p[0] = 'H'; printf("%s", p); }

A. Compile error

B. "Hello world"

C. Runtime error.

D. "hello world"
________________________________________

79 . main() { char * strA; char * strB = I am OK; memcpy( strA, strB, 6); }

A. Compile error

B. I am OK

C. Runtime error.

D. I am O
________________________________________
80 . How will you print % character?

thanks

Hau oi ong post not cai bai 3 nhap day so nguyen len di.